What is (\partial)/(\partial x)(sin(2x+3y+z)) ?

The answer to (\partial)/(\partial x)(sin(2x+3y+z)) is cos(2x+3y+z)*2

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(\partial)/(\partial x)(sin(2x+3y+z))

\frac{\partial}{\partial x} (sin (2 x + 3 y + z))

cos (2 x + 3 y + z) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x + 3 y + z))

Treat

y, z

as constants

Apply the chain rule:

cos (2 x + 3 y + z) \frac{\partial}{\partial x} (2 x + 3 y + z)

= cos (2 x + 3 y + z) \frac{\partial}{\partial x} (2 x + 3 y + z)

\frac{\partial}{\partial x} (2 x + 3 y + z) = 2

= cos (2 x + 3 y + z) \cdot 2

x \to 3 lim (ln (x + 3))

\int \frac{2 x ^{2} - 7 x - 1}{( x - 1 ) ( x + 1 ) ^{2}} d x

y^{^{'}} = \frac{5 x ^{3} + y ^{3}}{x y ^{2}}

\int 3 cos (7 x) d x

y^{^{''}} + 49 y^{^{'}} = 0

What is (\partial)/(\partial x)(sin(2x+3y+z)) ?
The answer to (\partial)/(\partial x)(sin(2x+3y+z)) is cos(2x+3y+z)*2