What is the derivative of y=(2x^4+7)^2 ?

The derivative of y=(2x^4+7)^2 is 16x^3(2x^4+7)

What is the first derivative of y=(2x^4+7)^2 ?

The first derivative of y=(2x^4+7)^2 is 16x^3(2x^4+7)

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derivative of

y = (2 x^{4} + 7)^{2}

16 x^{3} (2 x^{4} + 7)

Solution steps

\frac{d}{d x} ((2 x^{4} + 7)^{2})

Apply the chain rule:

2 (2 x^{4} + 7) \frac{d}{d x} (2 x^{4} + 7)

= 2 (2 x^{4} + 7) \frac{d}{d x} (2 x^{4} + 7)

\frac{d}{d x} (2 x^{4} + 7) = 8 x^{3}

= 2 (2 x^{4} + 7) \cdot 8 x^{3}

Simplify

= 16 x^{3} (2 x^{4} + 7)

\int \frac{y}{y ^{2} - 2 y - 3} d y

\frac{d}{d x} (f (x) (g (x)))

\int (4 x + 5)^{3} d x

e^{- \frac{x ^{2}}{2}}

\frac{d}{d x} ((4 x^{3} + 3)^{2})

What is the derivative of y=(2x^4+7)^2 ?
The derivative of y=(2x^4+7)^2 is 16x^3(2x^4+7)
What is the first derivative of y=(2x^4+7)^2 ?
The first derivative of y=(2x^4+7)^2 is 16x^3(2x^4+7)