What is the integral of sec(7x)tan(7x) ?

The integral of sec(7x)tan(7x) is 1/7 sec(7x)+C

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integral of sec(7x)tan(7x)

\int sec (7 x) tan (7 x) d x

\frac{1}{7} sec (7 x) + C

Solution steps

\int sec (7 x) tan (7 x) d x

Apply u-substitution

: \int \frac{1}{7} d u

= \int \frac{1}{7} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{7} u

Substitute back

u = sec (7 x)

= \frac{1}{7} sec (7 x)

Add a constant to the solution

= \frac{1}{7} sec (7 x) + C

\int y \cdot sin (y^{2}) d y

y = x^{3}, y = x

n = 0 \sum \infty n (\frac{1}{2})^{n}

\frac{d}{d x} (\frac{1}{y} e^{x y} - ln (y^{2}))

\frac{d}{d x} (7 x^{\frac{1}{2}} + x^{\frac{3}{2}})

What is the integral of sec(7x)tan(7x) ?
The integral of sec(7x)tan(7x) is 1/7 sec(7x)+C