What is the sum from n=1 to infinity of arctan(2n) ?

The sum from n=1 to infinity of arctan(2n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of arctan(2n)

n = 1 \sum \infty arctan (2 n)

diverges

Solution steps

n = 1 \sum \infty arctan (2 n)

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{2 ^{n}}{5 ^{n}}

\int \frac{5}{x ^{2} + 16} d x

\frac{9}{x ^{4}}, x \geq 1

\int_{- 4}^{6} (\frac{x}{2} + 6) d x

\frac{d}{d x} (4^{- 5 x^{3}})

What is the sum from n=1 to infinity of arctan(2n) ?
The sum from n=1 to infinity of arctan(2n) is diverges