What is the derivative of 9x^3 ?

The derivative of 9x^3 is 27x^2

What is the first derivative of 9x^3 ?

The first derivative of 9x^3 is 27x^2

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derivative of

9 x^{3}

27 x^{2}

Solution steps

\frac{d}{d x} (9 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot 3 x^{3 - 1}

Simplify

= 27 x^{2}

(x \cdot x - 1) y^{^{'}} - x y (1 - y) = 0

\frac{d}{d t} (\frac{3 t ^{2}}{1 + 4 t ^{2} + 9 t ^{4}})

\int e^{x^{2}} x^{3} d x

\frac{d}{d x} (a r (x) cos (e^{x}))

\int_{0}^{4} 2 π (2 - y) (4 y^{2}) d y