What is the derivative of f(x)=-8x^2 ?

The derivative of f(x)=-8x^2 is -16x

What is the first derivative of f(x)=-8x^2 ?

The first derivative of f(x)=-8x^2 is -16x

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derivative of

f (x) = - 8 x^{2}

- 16 x

Solution steps

\frac{d}{d x} (- 8 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 8 \cdot 2 x^{2 - 1}

Simplify

= - 16 x

y = 12 (ln (2 x) 3)

7 e^{2 t}

\frac{d}{d x} (x^{3} ln (2 x))

\int \frac{1}{2 - 8 x} d x

x \to 2 lim (- (\frac{\frac{1}{2}}{x - 2}))

What is the derivative of f(x)=-8x^2 ?
The derivative of f(x)=-8x^2 is -16x
What is the first derivative of f(x)=-8x^2 ?
The first derivative of f(x)=-8x^2 is -16x