What is the integral from 0 to 9 of sqrt(x)-1/3 x ?

The integral from 0 to 9 of sqrt(x)-1/3 x is 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 9 of sqrt(x)-1/3 x

\int_{0}^{9} x - \frac{1}{3} x d x

\frac{9}{2}

Solution steps

\int_{0}^{9} x - \frac{1}{3} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{9} x d x - \int_{0}^{9} \frac{1}{3} x d x

\int_{0}^{9} x d x = 18

\int_{0}^{9} \frac{1}{3} x d x = \frac{27}{2}

= 18 - \frac{27}{2}

Simplify

18 - \frac{27}{2} : \frac{9}{2}

= \frac{9}{2}

\frac{d y}{d t} = - 2 y

\frac{d}{d x} (\frac{1 + x ^{2} + x ^{4}}{1 + x + x ^{2}})

\int \frac{x + 3}{x ( x - 1 ) ( x + 4 )} d x

\int e^{1 - x} d x

What is the integral from 0 to 9 of sqrt(x)-1/3 x ?
The integral from 0 to 9 of sqrt(x)-1/3 x is 9/2