What is (\partial)/(\partial x)(ln(x^6+y^7)) ?

The answer to (\partial)/(\partial x)(ln(x^6+y^7)) is (6x^5)/(x^6+y^7)

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(\partial)/(\partial x)(ln(x^6+y^7))

\frac{\partial}{\partial x} (ln (x^{6} + y^{7}))

\frac{6 x ^{5}}{x ^{6} + y ^{7}}

Solution steps

\frac{\partial}{\partial x} (ln (x^{6} + y^{7}))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{x ^{6} + y ^{7}} \frac{\partial}{\partial x} (x^{6} + y^{7})

= \frac{1}{x ^{6} + y ^{7}} \frac{\partial}{\partial x} (x^{6} + y^{7})

\frac{\partial}{\partial x} (x^{6} + y^{7}) = 6 x^{5}

= \frac{1}{x ^{6} + y ^{7}} \cdot 6 x^{5}

Simplify

\frac{1}{x ^{6} + y ^{7}} \cdot 6 x^{5} : \frac{6 x ^{5}}{x ^{6} + y ^{7}}

= \frac{6 x ^{5}}{x ^{6} + y ^{7}}

\frac{d}{d x} (3 arcsin (x^{4}))

\int \frac{2 x ^{3}}{1 + x ^{4}} d x

\frac{1}{2 + x}

\int 7 x^{\frac{2}{5}} + 6 x^{- \frac{4}{5}} d x

What is (\partial)/(\partial x)(ln(x^6+y^7)) ?
The answer to (\partial)/(\partial x)(ln(x^6+y^7)) is (6x^5)/(x^6+y^7)