What is the solution for (dy)/(dx)= 1/2 y^3 ?

The solution for (dy)/(dx)= 1/2 y^3 is y=sqrt(-1/(x+c_{1))},y=-sqrt(-1/(x+c_{1))}

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(dy)/(dx)= 1/2 y^3

\frac{d y}{d x} = \frac{1}{2} y^{3}

y = - \frac{1}{x + c _{1}}, y = - - \frac{1}{x + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{1}{2} y^{3}

Solve separable ODE:

y = - \frac{1}{x + c _{1}}, y = - - \frac{1}{x + c _{1}}

y = - \frac{1}{x + c _{1}}, y = - - \frac{1}{x + c _{1}}

\frac{\partial}{\partial x} (cos^{7} (x^{9} y^{8}))

\frac{1}{e ^{x}}

(y^{3} - 1) e^{x} + 3 y^{2} (e^{x} + 1) \frac{d y}{d x} = 0, y (0) = 2

y^{^{''}} - 2 y^{^{'}} - 12 y = 0

\frac{d}{d x} (\frac{5}{3} x^{3})

What is the solution for (dy)/(dx)= 1/2 y^3 ?
The solution for (dy)/(dx)= 1/2 y^3 is y=sqrt(-1/(x+c_{1))},y=-sqrt(-1/(x+c_{1))}