en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^{''}-2xy^'+2y=0

Solution

x^{2} y^{^{''}} - 2 x y^{^{'}} + 2 y = 0

Solution

y = c_{1} x^{2} + c_{2} x

Solution steps

x^{2} y^{''} (x) - 2 x y^{'} (x) + 2 y = 0

Solve linear ODE:

y = c_{1} x^{2} + c_{2} x

y = c_{1} x^{2} + c_{2} x

Popular Examples

area f(x)=-x^2+6x-8,4,-2 area

f (x) = - x^{2} + 6 x - 8, 4, - 2

integral of 1/(sqrt(6x+1))

\int \frac{1}{6 x + 1} d x

integral from 0 to 6 of te^{-t}

\int_{0}^{6} t e^{- t} d t

(\partial)/(\partial x)(we^{x^2+y^2}ln(z))

\frac{\partial}{\partial x} (w e^{x^{2} + y^{2}} ln (z))

integral of y/(sqrt(25-36y^4))

\int \frac{y}{25 - 36 y ^{4}} d y

Frequently Asked Questions (FAQ)

What is the solution for x^2y^{''}-2xy^'+2y=0 ?
The solution for x^2y^{''}-2xy^'+2y=0 is y=c_{1}x^2+c_{2}x