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Popular >

derivative of in(x^2+1)

Solution

\frac{d}{d x} (in (x^{2} + 1))

Solution

2 in x

Solution steps

\frac{d}{d x} (in (x^{2} + 1))

Simplify

in (x^{2} + 1) : i (n + n x^{2})

= \frac{d}{d x} (i (n + n x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= i \frac{d}{d x} (n + n x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= i (\frac{d n}{d x} + \frac{d}{d x} (n x^{2}))

\frac{d n}{d x} = 0

\frac{d}{d x} (n x^{2}) = 2 n x

= i (0 + 2 n x)

Simplify

= 2 in x

Popular Examples

(dy)/(dx)=y^2+1

\frac{d y}{d x} = y^{2} + 1

derivative of e^{(-x^2/8})

\frac{d}{d x} (e^{\frac{- x ^{2}}{8}})

integral of (ln(x))^4 1/x

\int (ln (x))^{4} \frac{1}{x} d x

integral from 3 to 4 of x/(x^2-1)

\int_{3}^{4} \frac{x}{x ^{2} - 1} d x

integral of 1/((x-3))

\int \frac{1}{( x - 3 )} d x

Frequently Asked Questions (FAQ)

What is the derivative of in(x^2+1) ?
The derivative of in(x^2+1) is 2inx
What is the first derivative of in(x^2+1) ?
The first derivative of in(x^2+1) is 2inx