What is (\partial)/(\partial x)(2xe^{xy}) ?

The answer to (\partial)/(\partial x)(2xe^{xy}) is 2(e^{xy}+e^{xy}xy)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2xe^{xy})

\frac{\partial}{\partial x} (2 x e^{x y})

2 (e^{x y} + e^{x y} x y)

Solution steps

\frac{\partial}{\partial x} (2 x e^{x y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (x e^{x y})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x y}

= 2 (\frac{\partial}{\partial x} (x) e^{x y} + \frac{\partial}{\partial x} (e^{x y}) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (e^{x y}) = e^{x y} y

= 2 (1 \cdot e^{x y} + e^{x y} y x)

Simplify

= 2 (e^{x y} + e^{x y} x y)

9 z^{2} e^{z}

\int x^{5} ln (8 x) d x

\int \frac{1}{7 x ( ln ( 5 x ) ) ^{6}} d x

y = e^{x} 1 0^{x}

\int \frac{1}{25 + 9 x ^{2}} d x

What is (\partial)/(\partial x)(2xe^{xy}) ?
The answer to (\partial)/(\partial x)(2xe^{xy}) is 2(e^{xy}+e^{xy}xy)