What is inverse oflaplace 2/(s^2+4) ?

The answer to inverse oflaplace 2/(s^2+4) is sin(2t)

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inverse oflaplace 2/(s^2+4)

inverse laplace

\frac{2}{s ^{2} + 4}

sin (2 t)

Solution steps

L^{- 1} {\frac{2}{s ^{2} + 4}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s ^{2} + a ^{2}}} = sin (a t)

L^{- 1} {\frac{2}{s ^{2} + 2 ^{2}}} = sin (2 t)

= sin (2 t)

\int_{0}^{4} x e^{x + 2} d x

\int \frac{5 - 3 sin ( 2 x )}{sec ( 6 x )} d x

\int (\frac{x ^{2} + 1}{x}) d x

\frac{1}{4 + x ^{2}}

\int_{0}^{\frac{π}{2}} (sin^{3} (x)) d x

What is inverse oflaplace 2/(s^2+4) ?
The answer to inverse oflaplace 2/(s^2+4) is sin(2t)