What is the derivative of a-bx^2 ?

The derivative of a-bx^2 is -2bx

What is the first derivative of a-bx^2 ?

The first derivative of a-bx^2 is -2bx

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\frac{d}{d x} (a - b x^{2})

- 2 b x

Solution steps

\frac{d}{d x} (a - b x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d a}{d x} - \frac{d}{d x} (b x^{2})

\frac{d a}{d x} = 0

\frac{d}{d x} (b x^{2}) = 2 b x

= 0 - 2 b x

Simplify

= - 2 b x

\int_{1}^{2} (2 x - 3)^{2} d x

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\frac{2}{3 s ^{2} + 6 s + 2}

\int 1 + 2 sin (\frac{x ^{2}}{2}) d x