What is the tangent of y=sin(x)cos(x) ?

The tangent of y=sin(x)cos(x) is y=cos(2a_{0})x+sin(a_{0})cos(a_{0})-cos(2a_{0})a_{0}

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tangent of y=sin(x)cos(x)

tangent of

y = sin (x) cos (x)

y = cos (2 a_{0}) x + sin (a_{0}) cos (a_{0}) - cos (2 a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, sin (a_{0}) cos (a_{0}))

Find the slope of

y = sin (x) cos (x) : \frac{d y}{d x} = cos (2 x)

Compute the slope of

y = sin (x) cos (x)

x = a_{0} : m = cos (2 a_{0})

Find the line with slope m=

cos (2 a_{0})

and passing through

(a_{0}, sin (a_{0}) cos (a_{0})) : y = cos (2 a_{0}) x + sin (a_{0}) cos (a_{0}) - cos (2 a_{0}) a_{0}

y = cos (2 a_{0}) x + sin (a_{0}) cos (a_{0}) - cos (2 a_{0}) a_{0}

\int \frac{1}{x} + x d x

y^{^{'}} - 6 y = 0

\frac{\partial}{\partial x} (x^{0.2} \cdot y^{0.8})

\int 4 cos (x - 1) d x

\int \frac{1}{x ^{2} + 2 x + 17} d x

What is the tangent of y=sin(x)cos(x) ?
The tangent of y=sin(x)cos(x) is y=cos(2a_{0})x+sin(a_{0})cos(a_{0})-cos(2a_{0})a_{0}