What is the first derivative of-2x-4 ?

The first derivative of-2x-4 is -2

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derivative of-2x-4

\frac{d}{d x} (- 2 x - 4)

- 2

Solution steps

\frac{d}{d x} (- 2 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= - 2 - 0

Simplify

= - 2

x \to 1 lim (\frac{cos ( π x )}{3})

f^{^{'}} (x) = e^{3 x + 2} - 3 x^{2}

\int x y^{2} - x^{2} d x

7 x, 8 x^{2}

\frac{\partial}{\partial y} (4 e^{x} cos (yz))