What is the solution for y^{''}+36y=24sin(6t) ?

The solution for y^{''}+36y=24sin(6t) is y=c_{1}cos(6t)+c_{2}sin(6t)-2tcos(6t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+36y=24sin(6t)

y^{^{''}} + 36 y = 24 sin (6 t)

y = c_{1} cos (6 t) + c_{2} sin (6 t) - 2 t cos (6 t)

Solution steps

y^{''} (t) + 36 y = 24 sin (6 t)

Solve linear ODE:

y = c_{1} cos (6 t) + c_{2} sin (6 t) - 2 t cos (6 t)

y = c_{1} cos (6 t) + c_{2} sin (6 t) - 2 t cos (6 t)

y = \frac{1}{7 t ^{3}}

x \to 1 + lim ((1 - x)^{l n (x)})

\int_{2}^{3} \frac{38}{3 - x} d x

3 \frac{d y}{d x} = y^{2}

t \to 0 lim (2 t)

What is the solution for y^{''}+36y=24sin(6t) ?
The solution for y^{''}+36y=24sin(6t) is y=c_{1}cos(6t)+c_{2}sin(6t)-2tcos(6t)