What is the tangent of y=cos(x),\at x=2pi ?

The tangent of y=cos(x),\at x=2pi is y=1

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tangent of y=cos(x),\at x=2pi

tangent of

y = cos (x), at x = 2 π

y = 1

Solution steps

Find the tangent point:

(2 π, 1)

Find the slope of

y = cos (x) : \frac{d y}{d x} = - sin (x)

Compute the slope of

y = cos (x)

x = 2 π : m = 0

Find the line with slope m=

0

and passing through

(2 π, 1) : y = 1

y = 1

\frac{d}{d x} (- 8 sin (8 x))

\frac{d}{d x} ((5 x^{3} + 8 x - 3)^{\frac{3}{2}})

\frac{d}{d x} (2^{x})

3 \frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + y = 0

5 x - 2 x

What is the tangent of y=cos(x),\at x=2pi ?
The tangent of y=cos(x),\at x=2pi is y=1