What is the solution for 2x^2(dy)/(dx)=3xy+y^2 ?

The solution for 2x^2(dy)/(dx)=3xy+y^2 is y=(x^{1/2}(c_{1}x+x^{3/2}))/(c_{1)^2-x}

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2x^2(dy)/(dx)=3xy+y^2

2 x^{2} \frac{d y}{d x} = 3 x y + y^{2}

y = \frac{x ^{\frac{1}{2}} ( c _{1} x + x ^{\frac{3}{2}} )}{c _{1}^{2} - x}

Solution steps

2 x^{2} \frac{d y}{d x} = 3 x y + y^{2}

Solve Bernoulli ODE:

y = \frac{x ^{\frac{1}{2}} ( c _{1} x + x ^{\frac{3}{2}} )}{c _{1}^{2} - x}

y = \frac{x ^{\frac{1}{2}} ( c _{1} x + x ^{\frac{3}{2}} )}{c _{1}^{2} - x}

\frac{d}{d t} (cos (t) - t sin (t))

cos (sin (tan (3 x)))

\frac{2}{5 ( s + 1 ) ^{2} - 80}

x \to 2 lim (\frac{1 - x ^{2}}{1 - x})

What is the solution for 2x^2(dy)/(dx)=3xy+y^2 ?
The solution for 2x^2(dy)/(dx)=3xy+y^2 is y=(x^{1/2}(c_{1}x+x^{3/2}))/(c_{1)^2-x}