What is the derivative of-sin(4x*4) ?

The derivative of-sin(4x*4) is -16cos(4x)

What is the first derivative of-sin(4x*4) ?

The first derivative of-sin(4x*4) is -16cos(4x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- sin (4 x) \cdot 4)

- 16 cos (4 x)

Solution steps

\frac{d}{d x} (- sin (4 x) \cdot 4)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - 4 cos (4 x) \cdot 4

Simplify

= - 16 cos (4 x)

\int \frac{x + 17}{x ^{2} + 16 x + 68} d x

\int \frac{( 4 x + 13 )}{( x ^{2} + 3 x - 10 )} d x

\int t^{3} e^{- t^{2}} d t

5 tan^{2} (7 x)

\int \frac{5 x + 3}{x ^{3} - 2 x ^{2} - 3 x} d x

What is the derivative of-sin(4x*4) ?
The derivative of-sin(4x*4) is -16cos(4x)
What is the first derivative of-sin(4x*4) ?
The first derivative of-sin(4x*4) is -16cos(4x)