What is the tangent of 6x^2,\at x=10 ?

The tangent of 6x^2,\at x=10 is y=120x-600

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tangent of 6x^2,\at x=10

tangent of

6 x^{2}, at x = 10

y = 120 x - 600

Solution steps

Find the tangent point:

(10, 600)

Find the slope of

y = 6 x^{2} : \frac{d y}{d x} = 12 x

Compute the slope of

y = 6 x^{2}

x = 10 : m = 120

Find the line with slope m=

120

and passing through

(10, 600) : y = 120 x - 600

y = 120 x - 600

22 cos (t)

\int x^{2} - 4 x + 2 d x

\int \frac{3}{x} d x

\int sin (θ) \cdot cos (θ) d θ

\int 2 x - 2 d x

What is the tangent of 6x^2,\at x=10 ?
The tangent of 6x^2,\at x=10 is y=120x-600