What is the tangent of 6x^2,\at x=10 ?

The tangent of 6x^2,\at x=10 is y=120x-600

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of 6x^2,\at x=10

tangent of

6 x^{2}, at x = 10

y = 120 x - 600

Solution steps

Find the tangent point:

(10, 600)

Find the slope of

y = 6 x^{2} : \frac{d y}{d x} = 12 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 120

Find the line with slope m=

120

and passing through

(10, 600) : y = 120 x - 600

y = 120 x - 600

\int x^{2} - 4 x + 2 d x

\int sin (θ) \cdot cos (θ) d θ

\int 2 x - 2 d x

x^{2} \cdot e^{x}

x \to 2 + lim (\frac{9 x}{x - 2})

What is the tangent of 6x^2,\at x=10 ?
The tangent of 6x^2,\at x=10 is y=120x-600