What is the integral of sqrt(3/x) ?

The integral of sqrt(3/x) is sqrt(3/x)x+sqrt(3)sqrt(x)+C

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integral of sqrt(3/x)

\int \frac{3}{x} d x

\frac{3}{x} x + 3 x + C

Solution steps

\int \frac{3}{x} d x

Apply Integration By Parts

: \frac{3}{x} x - \int - \frac{3}{2 x ^{\frac{1}{2}}} d x

= \frac{3}{x} x - \int - \frac{3}{2 x ^{\frac{1}{2}}} d x

\int - \frac{3}{2 x ^{\frac{1}{2}}} d x = - 3 x

= \frac{3}{x} x - (- 3 x)

Simplify

= \frac{3}{x} x + 3 x

Add a constant to the solution

= \frac{3}{x} x + 3 x + C

\int sin (θ) \cdot cos (θ) d θ

\int 2 x - 2 d x

\int \frac{7}{x ^{6}} d x

x^{2} \cdot e^{x}

x \to 2 + lim (\frac{9 x}{x - 2})

What is the integral of sqrt(3/x) ?
The integral of sqrt(3/x) is sqrt(3/x)x+sqrt(3)sqrt(x)+C