What is the derivative of-3+12x-3x^2 ?

The derivative of-3+12x-3x^2 is -6x+12

What is the first derivative of-3+12x-3x^2 ?

The first derivative of-3+12x-3x^2 is -6x+12

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derivative of

- 3 + 12 x - 3 x^{2}

- 6 x + 12

Solution steps

\frac{d}{d x} (- 3 + 12 x - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3) + \frac{d}{d x} (12 x) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (3 x^{2}) = 6 x

= - 0 + 12 - 6 x

Simplify

= - 6 x + 12

x \to - 1 lim (3 x^{3})

\int sec^{3} (u) d u

\int \frac{1}{( 16 + x ^{2} ) ^{3}} d x

- 6 x = 10 - y - 36 x = 48 - 6 y

\int 4 cos^{2} (x) tan^{3} (x) d x

What is the derivative of-3+12x-3x^2 ?
The derivative of-3+12x-3x^2 is -6x+12
What is the first derivative of-3+12x-3x^2 ?
The first derivative of-3+12x-3x^2 is -6x+12