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Popular >

h^'=-h^{1/3}

Solution

h^{^{'}} = - h^{\frac{1}{3}}

Solution

h (t) = \frac{2 2 - t ^{3} + c _{1}^{3} + 3 c _{1} t ^{2} - 3 c _{1}^{2} t}{3 3}, h (t) = - \frac{2 2 - t ^{3} + c _{1}^{3} + 3 c _{1} t ^{2} - 3 c _{1}^{2} t}{3 3}

Solution steps

h^{'} (t) = - h (t)^{\frac{1}{3}}

Solve separable ODE:

h (t) = \frac{2 2 - t ^{3} + c _{1}^{3} + 3 c _{1} t ^{2} - 3 c _{1}^{2} t}{3 3}, h (t) = - \frac{2 2 - t ^{3} + c _{1}^{3} + 3 c _{1} t ^{2} - 3 c _{1}^{2} t}{3 3}

h (t) = \frac{2 2 - t ^{3} + c _{1}^{3} + 3 c _{1} t ^{2} - 3 c _{1}^{2} t}{3 3}, h (t) = - \frac{2 2 - t ^{3} + c _{1}^{3} + 3 c _{1} t ^{2} - 3 c _{1}^{2} t}{3 3}

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Frequently Asked Questions (FAQ)

What is the solution for h^'=-h^{1/3} ?
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