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Popular >

y^'=e^{5x+3y}

Solution

y^{^{'}} = e^{5 x + 3 y}

Solution

y = - \frac{ln ( - \frac{3}{5} e ^{5 x} - c _{1} )}{3}

Solution steps

y^{'} (x) = e^{5 x + 3 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{3}{5} e ^{5 x} - c _{1} )}{3}

y = - \frac{ln ( - \frac{3}{5} e ^{5 x} - c _{1} )}{3}

Popular Examples

f (t) = cos^{3} (t)

y^{''}-y^'-2y=e^{3x}sin(2x)

y^{^{''}} - y^{^{'}} - 2 y = e^{3 x} sin (2 x)

y^{''}+y=tan(t)+e^{3t}-1

y^{^{''}} + y = tan (t) + e^{3 t} - 1

(\partial)/(\partial u)(u/v)

\frac{\partial}{\partial u} (\frac{u}{v})

(\partial)/(\partial y)(y^2-2ycos(x))

\frac{\partial}{\partial y} (y^{2} - 2 y cos (x))

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{5x+3y} ?
The solution for y^'=e^{5x+3y} is y=-(ln(-3/5 e^{5x}-c_{1}))/3