What is the derivative of 9/(4-x) ?

The derivative of 9/(4-x) is 9/((4-x)^2)

What is the first derivative of 9/(4-x) ?

The first derivative of 9/(4-x) is 9/((4-x)^2)

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\frac{d}{d x} (\frac{9}{4 - x})

\frac{9}{( 4 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{4 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{4 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((4 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 - x ) ^{2}} \frac{d}{d x} (4 - x)

= - \frac{1}{( 4 - x ) ^{2}} \frac{d}{d x} (4 - x)

\frac{d}{d x} (4 - x) = - 1

= 9 (- \frac{1}{( 4 - x ) ^{2}} (- 1))

Simplify

9 (- \frac{1}{( 4 - x ) ^{2}} (- 1)) : \frac{9}{( 4 - x ) ^{2}}

= \frac{9}{( 4 - x ) ^{2}}

f (x) = 3 x^{3}, at x = 3

\frac{\partial}{\partial x} (x^{2} e^{y} + x - 2 y)

\int \frac{x ^{2} + 2 x + 1}{x ^{3} + x} d x

\frac{d y}{d x} = e^{y - x^{2} + 1}

\int 169 - t^{2} d t

What is the derivative of 9/(4-x) ?
The derivative of 9/(4-x) is 9/((4-x)^2)
What is the first derivative of 9/(4-x) ?
The first derivative of 9/(4-x) is 9/((4-x)^2)