What is the solution for (2y-3x)(dy)/(dx)=3y-4x ?

The solution for (2y-3x)(dy)/(dx)=3y-4x is y=(3x+sqrt(x^2+c_{1)})/2 ,y=(3x-sqrt(x^2+c_{1)})/2

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(2y-3x)(dy)/(dx)=3y-4x

(2 y - 3 x) \frac{d y}{d x} = 3 y - 4 x

y = \frac{3 x + x ^{2} + c _{1}}{2}, y = \frac{3 x - x ^{2} + c _{1}}{2}

Solution steps

(2 y - 3 x) \frac{d y}{d x} = 3 y - 4 x

Solve exact ODE:

y = \frac{3 x + x ^{2} + c _{1}}{2}, y = \frac{3 x - x ^{2} + c _{1}}{2}

y = \frac{3 x + x ^{2} + c _{1}}{2}, y = \frac{3 x - x ^{2} + c _{1}}{2}

\int_{- \infty}^{0} e^{- ∣ x ∣} d x

\frac{\partial}{\partial y} (x e^{2 y x})

\frac{\partial}{\partial y} (2 + x ln (x y - 5))

\int \frac{1}{x ^{2} - 8 x - 12} d x

y^{^{''}} + 2 y^{^{'}} + y = x^{- 6} e^{- x}

What is the solution for (2y-3x)(dy)/(dx)=3y-4x ?
The solution for (2y-3x)(dy)/(dx)=3y-4x is y=(3x+sqrt(x^2+c_{1)})/2 ,y=(3x-sqrt(x^2+c_{1)})/2