What is the derivative of f(x)= 1/(1+x) ?

The derivative of f(x)= 1/(1+x) is -1/((1+x)^2)

What is the first derivative of f(x)= 1/(1+x) ?

The first derivative of f(x)= 1/(1+x) is -1/((1+x)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{1}{1 + x}

- \frac{1}{( 1 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{1 + x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((1 + x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 + x ) ^{2}} \frac{d}{d x} (1 + x)

= - \frac{1}{( 1 + x ) ^{2}} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= - \frac{1}{( 1 + x ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( 1 + x ) ^{2}}

4 y^{^{''}} - 5 y^{^{'}} = 0

\frac{1}{x x ^{2} - 1}, x = \frac{2}{2}, x = 2

(\frac{5}{x})^{^{'}}

\int sin (3 x) ln (cos (3 x)) d x

\frac{d}{d x} ((4 x^{2} + 2 x - 5) (x^{3} + 7 x + 4))

What is the derivative of f(x)= 1/(1+x) ?
The derivative of f(x)= 1/(1+x) is -1/((1+x)^2)
What is the first derivative of f(x)= 1/(1+x) ?
The first derivative of f(x)= 1/(1+x) is -1/((1+x)^2)