en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of f(x)=acos(2x)+bsin(2x)

Solution

derivative of

f (x) = a cos (2 x) + b sin (2 x)

Solution

- 2 a sin (2 x) + b cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (a cos (2 x) + b sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos (2 x)) + \frac{d}{d x} (b sin (2 x))

\frac{d}{d x} (a cos (2 x)) = - 2 a sin (2 x)

\frac{d}{d x} (b sin (2 x)) = b cos (2 x) \cdot 2

= - 2 a sin (2 x) + b cos (2 x) \cdot 2

Popular Examples

(\partial)/(\partial y)(x^3e^{-2y})

\frac{\partial}{\partial y} (x^{3} e^{- 2 y})

integral of (900)/((2q-5)^2)

\int \frac{900}{( 2 q - 5 ) ^{2}} d q

derivative of 5/3 x^2

\frac{d}{d x} (\frac{5}{3} x^{2})

limit as x approaches 0 of x*sin(x)

x \to 0 lim (x \cdot sin (x))

integral from 1 to infinity of 15e^{-5x}

\int_{1}^{\infty} 15 e^{- 5 x} d x

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=acos(2x)+bsin(2x) ?
The derivative of f(x)=acos(2x)+bsin(2x) is -2asin(2x)+bcos(2x)*2
What is the first derivative of f(x)=acos(2x)+bsin(2x) ?
The first derivative of f(x)=acos(2x)+bsin(2x) is -2asin(2x)+bcos(2x)*2