What is the derivative of 2t^{3pi} ?

The derivative of 2t^{3pi} is 6pit^{3pi-1}

What is the first derivative of 2t^{3pi} ?

The first derivative of 2t^{3pi} is 6pit^{3pi-1}

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derivative of

2 t^{3 π}

6 π t^{3 π - 1}

Solution steps

\frac{d}{d t} (2 t^{3 π})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t^{3 π})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 3 π t^{3 π - 1}

Simplify

= 6 π t^{3 π - 1}

\int_{1}^{4} \frac{x - 1}{x} d x

\frac{1}{2} + 2 sin (x) + 2 cos (x)

25 y^{^{''}} + 11 y = 0

x \to 2 - lim (\frac{1}{x ^{2} - 9})

\int \frac{- 2 x ^{3} + x}{- 4 x ^{4} + 4 x ^{2}} d x

What is the derivative of 2t^{3pi} ?
The derivative of 2t^{3pi} is 6pit^{3pi-1}
What is the first derivative of 2t^{3pi} ?
The first derivative of 2t^{3pi} is 6pit^{3pi-1}