What is the integral of sin^{10}(x)cos(x) ?

The integral of sin^{10}(x)cos(x) is (sin^{11}(x))/(11)+C

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integral of sin^{10}(x)cos(x)

\int sin^{10} (x) cos (x) d x

\frac{sin ^{11} ( x )}{11} + C

Solution steps

\int sin^{10} (x) cos (x) d x

Apply u-substitution

: \int u^{10} d u

= \int u^{10} d u

Apply the Power Rule

: \frac{u ^{11}}{11}

= \frac{u ^{11}}{11}

Substitute back

u = sin (x)

= \frac{sin ^{11} ( x )}{11}

Add a constant to the solution

= \frac{sin ^{11} ( x )}{11} + C

\int \frac{x - 3}{x} d x

\frac{d}{d x} (2 x^{2} + 8 x)

x (x^{2} - 11 x + 35), x^{2}

\frac{d}{d x} (\frac{3}{4} x^{12})

y^{^{'}} = - \frac{1}{x} y^{2} - \frac{1}{x} y

What is the integral of sin^{10}(x)cos(x) ?
The integral of sin^{10}(x)cos(x) is (sin^{11}(x))/(11)+C