What is the tangent of x^{2/3}+y^{2/3}=5,(-8,-1) ?

The tangent of x^{2/3}+y^{2/3}=5,(-8,-1) is y=-1/2 x-5

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tangent of x^{2/3}+y^{2/3}=5,(-8,-1)

tangent of

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 5, (- 8, - 1)

y = - \frac{1}{2} x - 5

Solution steps

Find the slope of

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 5 : \frac{d y}{d x} = - (\frac{y}{x})^{\frac{1}{3}}

Compute the slope of

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 5

(- 8, - 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(- 8, - 1) : y = - \frac{1}{2} x - 5

y = - \frac{1}{2} x - 5

\int_{1}^{3} x^{4} ln (x) d x

\frac{d y}{d t} = 5 y + y^{4}

\int \frac{x}{100} d x

\frac{\partial}{\partial x} (y - 4 x^{2} y^{- 2})

\frac{\partial ^{2}}{\partial x ^{2}} (ln (3 + x^{2} y^{2}))

What is the tangent of x^{2/3}+y^{2/3}=5,(-8,-1) ?
The tangent of x^{2/3}+y^{2/3}=5,(-8,-1) is y=-1/2 x-5