What is the derivative of 4x^3+6x^2 ?

The derivative of 4x^3+6x^2 is 12x^2+12x

What is the first derivative of 4x^3+6x^2 ?

The first derivative of 4x^3+6x^2 is 12x^2+12x

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derivative of

4 x^{3} + 6 x^{2}

12 x^{2} + 12 x

Solution steps

\frac{d}{d x} (4 x^{3} + 6 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (6 x^{2})

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

= 12 x^{2} + 12 x

\frac{\partial}{\partial x} (6 x + 3 y - 7)

\frac{d}{d y} (2 e^{y})

x y + y^{^{'}} = 78 x

\int_{0}^{1} 2^{u} 2 u d u

\int x (1 + x^{2}) d x

What is the derivative of 4x^3+6x^2 ?
The derivative of 4x^3+6x^2 is 12x^2+12x
What is the first derivative of 4x^3+6x^2 ?
The first derivative of 4x^3+6x^2 is 12x^2+12x