What is the limit as t approaches 0 of (4e^t-4)/t ?

The limit as t approaches 0 of (4e^t-4)/t is 4

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limit as t approaches 0 of (4e^t-4)/t

t \to 0 lim (\frac{4 e ^{t} - 4}{t})

4

Solution steps

t \to 0 lim (\frac{4 e ^{t} - 4}{t})

Apply L'Hopital's Rule

: t \to 0 lim (\frac{4 e ^{t}}{1})

= t \to 0 lim (\frac{4 e ^{t}}{1})

Plug in the value

t = 0

= \frac{4 e ^{0}}{1}

Simplify

= 4

\frac{s + 1}{( s + 2 ) ^{2}}

x \to - 2 lim (\frac{2 x + 4}{x - 2})

\frac{\partial}{\partial y} (ln (x^{3} + 1) + y^{2})

\int_{- 2}^{- 1} 15 x^{- 4} d x

\frac{d}{d x} (f (x) (x^{3}))

What is the limit as t approaches 0 of (4e^t-4)/t ?
The limit as t approaches 0 of (4e^t-4)/t is 4