What is the limit as z approaches 0 of (2z-8)^{1/3} ?

The limit as z approaches 0 of (2z-8)^{1/3} is 2(-1)^{1/3}

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limit as z approaches 0 of (2z-8)^{1/3}

z \to 0 lim ((2 z - 8)^{\frac{1}{3}})

2 (- 1)^{\frac{1}{3}}

Solution steps

z \to 0 lim ((2 z - 8)^{\frac{1}{3}})

Plug in the value

z = 0

= (2 \cdot 0 - 8)^{\frac{1}{3}}

Simplify

(2 \cdot 0 - 8)^{\frac{1}{3}} : 2 (- 1)^{\frac{1}{3}}

= 2 (- 1)^{\frac{1}{3}}

\frac{d}{d x} (\frac{2}{3} (1 - x)^{\frac{3}{2}})

y^{^{'}} = - 2 x tan (y), y (0) = \frac{π}{2}

\int \frac{( x + 3 ) ^{2}}{x + 2} d x

\frac{d}{d x} (tan (x) ln (x))

x \to 3 lim (4 x^{3} - 3 x^{2} + x - 5)

What is the limit as z approaches 0 of (2z-8)^{1/3} ?
The limit as z approaches 0 of (2z-8)^{1/3} is 2(-1)^{1/3}