What is the derivative of x^4+2x^2+1 ?

The derivative of x^4+2x^2+1 is 4x^3+4x

What is the first derivative of x^4+2x^2+1 ?

The first derivative of x^4+2x^2+1 is 4x^3+4x

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\frac{d}{d x} (x^{4} + 2 x^{2} + 1)

4 x^{3} + 4 x

Solution steps

\frac{d}{d x} (x^{4} + 2 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 4 x^{3} + 4 x + 0

Simplify

= 4 x^{3} + 4 x

\frac{d}{d t} (\frac{cos ( t )}{t})

\int_{0}^{1} x^{2} e^{- x} d x

\int (x - 4)^{3} d x

\frac{d}{d x} (\frac{tan ( x )}{e ^{x}})

x \to - 1 lim (\frac{x + 4}{2 x + 1})

What is the derivative of x^4+2x^2+1 ?
The derivative of x^4+2x^2+1 is 4x^3+4x
What is the first derivative of x^4+2x^2+1 ?
The first derivative of x^4+2x^2+1 is 4x^3+4x