What is the integral of sec(u)tan(u) ?

The integral of sec(u)tan(u) is sec(u)+C

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integral of sec(u)tan(u)

\int sec (u) tan (u) d u

sec (u) + C

Solution steps

\int sec (u) tan (u) d u

Apply u-substitution

: \int 1 d v

= \int 1 d v

Integral of a constant:

\int a d x = a x

= 1 \cdot v

Substitute back

v = sec (u)

= 1 \cdot sec (u)

Simplify

= sec (u)

Add a constant to the solution

= sec (u) + C

x \to 7 + lim (\frac{∣ x - 7 ∣}{x - 7})

lo g_{3} (x^{3} + 1)

\frac{d}{d x} (\frac{x}{3})

y = 2 x, [4, 9]

\frac{d}{d x} ((3 x^{2} + 2 x - 1)^{4})