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Popular >

(dy)/(dt)=(y^2+1)t

Solution

\frac{d y}{d t} = (y^{2} + 1) t

Solution

y = tan (\frac{t ^{2}}{2} + c_{1})

Solution steps

\frac{d y}{d t} = (y^{2} + 1) t

Solve separable ODE:

y = tan (\frac{t ^{2}}{2} + c_{1})

y = tan (\frac{t ^{2}}{2} + c_{1})

Popular Examples

derivative of sqrt(10+x)

\frac{d}{d x} (10 + x)

integral from 0 to 1 of (51)/(4y-1)

\int_{0}^{1} \frac{51}{4 y - 1} d y

limit as x approaches 0 of 2/x-2/(x^2-x)

x \to 0 lim (\frac{2}{x} - \frac{2}{x ^{2} - x})

(\partial)/(\partial x)(xy^2z^2)

\frac{\partial}{\partial x} (x y^{2} z^{2})

limit as x approaches 2 of x^3-3x

x \to 2 lim (x^{3} - 3 x)

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)=(y^2+1)t ?
The solution for (dy)/(dt)=(y^2+1)t is y=tan((t^2)/2+c_{1})