What is the limit as x approaches 0 of (|x(h+1)|)/x ?

The limit as x approaches 0 of (|x(h+1)|)/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (|x(h+1)|)/x

x \to 0 lim (\frac{∣ x ( h + 1 ) ∣}{x})

diverges

Solution steps

x \to 0 lim (\frac{∣ x ( h + 1 ) ∣}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{∣ x ( h + 1 ) ∣}{x}) = ∣ h + 1 ∣

x \to 0 - lim (\frac{∣ x ( h + 1 ) ∣}{x}) = - ∣ h + 1 ∣

= diverges

\int_{0}^{8} \frac{x}{x ^{2} - 1} d x

\frac{\partial}{\partial y} (x^{4} + y^{4} - 4 x y + 2)

x + \frac{5}{x}

\int_{0}^{1} \frac{10}{4 y - 1} d y

x \to - 1 lim (ln (x))

What is the limit as x approaches 0 of (|x(h+1)|)/x ?
The limit as x approaches 0 of (|x(h+1)|)/x is diverges