What is the derivative of f(x)=(x-x^2) ?

The derivative of f(x)=(x-x^2) is 1-2x

What is the first derivative of f(x)=(x-x^2) ?

The first derivative of f(x)=(x-x^2) is 1-2x

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derivative of

f (x) = (x - x^{2})

1 - 2 x

Solution steps

\frac{d}{d x} ((x - x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (x^{2})

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2}) = 2 x

= 1 - 2 x

(y) d x + (y - x) d y = 0

x y^{^{'}} - 3 y + 12 = 0

y = \frac{5}{4 x + 1}, (1, 1)

\frac{1}{x - 1}, 23

What is the derivative of f(x)=(x-x^2) ?
The derivative of f(x)=(x-x^2) is 1-2x
What is the first derivative of f(x)=(x-x^2) ?
The first derivative of f(x)=(x-x^2) is 1-2x