What is the derivative of 8csc(5x^4-8x+6) ?

The derivative of 8csc(5x^4-8x+6) is -8cot(5x^4-8x+6)csc(5x^4-8x+6)(20x^3-8)

What is the first derivative of 8csc(5x^4-8x+6) ?

The first derivative of 8csc(5x^4-8x+6) is -8cot(5x^4-8x+6)csc(5x^4-8x+6)(20x^3-8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

8 csc (5 x^{4} - 8 x + 6)

- 8 cot (5 x^{4} - 8 x + 6) csc (5 x^{4} - 8 x + 6) (20 x^{3} - 8)

Solution steps

\frac{d}{d x} (8 csc (5 x^{4} - 8 x + 6))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (csc (5 x^{4} - 8 x + 6))

Apply the chain rule:

- cot (5 x^{4} - 8 x + 6) csc (5 x^{4} - 8 x + 6) \frac{d}{d x} (5 x^{4} - 8 x + 6)

= - cot (5 x^{4} - 8 x + 6) csc (5 x^{4} - 8 x + 6) \frac{d}{d x} (5 x^{4} - 8 x + 6)

\frac{d}{d x} (5 x^{4} - 8 x + 6) = 20 x^{3} - 8

= 8 (- cot (5 x^{4} - 8 x + 6) csc (5 x^{4} - 8 x + 6) (20 x^{3} - 8))

Simplify

= - 8 cot (5 x^{4} - 8 x + 6) csc (5 x^{4} - 8 x + 6) (20 x^{3} - 8)

n = 0 \sum \infty - \frac{1}{3 ^{n}}

x \to 0 lim (\frac{1}{x ^{2} + 1})

\frac{d}{d x} (sec^{2} (x) - 4)

\frac{d y}{d x} = \frac{1}{x ^{2}}

arcsin (\frac{x}{5})

What is the derivative of 8csc(5x^4-8x+6) ?
The derivative of 8csc(5x^4-8x+6) is -8cot(5x^4-8x+6)csc(5x^4-8x+6)(20x^3-8)
What is the first derivative of 8csc(5x^4-8x+6) ?
The first derivative of 8csc(5x^4-8x+6) is -8cot(5x^4-8x+6)csc(5x^4-8x+6)(20x^3-8)