What is partialfraction (x^2)/(1-x) ?

The solution to partialfraction (x^2)/(1-x) is -x-1+1/(-x+1)

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partialfraction (x^2)/(1-x)

partial fractions

\frac{x ^{2}}{1 - x}

- x - 1 + \frac{1}{- x + 1}

Solution steps

\frac{x ^{2}}{1 - x}

Long division

\frac{x ^{2}}{1 - x} : - x - 1 + \frac{1}{- x + 1}

= - x - 1 + \frac{1}{- x + 1}

- x - 1 + \frac{1}{- x + 1}

y^{^{''}} + 3 y^{^{'}} - 10 y = 6 e^{4 x}

\int_{0}^{2} \frac{1}{16 + x ^{2}} d x

\int \frac{x}{x - 9} d x

4 x^{2} + 2 x - 1, at x = 0

x y^{2} y^{^{'}} = x^{3} + 2 y^{3}

What is partialfraction (x^2)/(1-x) ?
The solution to partialfraction (x^2)/(1-x) is -x-1+1/(-x+1)