What is the derivative of \sqrt[6]{-x+1} ?

The derivative of \sqrt[6]{-x+1} is -1/(6(-x+1)^{5/6)}

What is the first derivative of \sqrt[6]{-x+1} ?

The first derivative of \sqrt[6]{-x+1} is -1/(6(-x+1)^{5/6)}

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derivative of

- \frac{1}{6 ( - x + 1 ) ^{\frac{5}{6}}}

Solution steps

Apply the chain rule:

\frac{1}{6 ( - x + 1 ) ^{\frac{5}{6}}} \frac{d}{d x} (- x + 1)

= \frac{1}{6 ( - x + 1 ) ^{\frac{5}{6}}} \frac{d}{d x} (- x + 1)

\frac{d}{d x} (- x + 1) = - 1

= \frac{1}{6 ( - x + 1 ) ^{\frac{5}{6}}} (- 1)

Simplify

= - \frac{1}{6 ( - x + 1 ) ^{\frac{5}{6}}}

\frac{d ^{2} x}{d t ^{2}} + 4 x = cos (3 t)

x \to 2 lim (4 - a \cdot x)

n = 0 \sum \infty 3 x^{n}

\int_{0}^{1} \frac{1}{1 + x ^{\frac{1}{3}}} d x

\frac{d ^{2}}{d x ^{2}} (sin (x) + cos (x))

What is the derivative of \sqrt[6]{-x+1} ?
The derivative of \sqrt[6]{-x+1} is -1/(6(-x+1)^{5/6)}
What is the first derivative of \sqrt[6]{-x+1} ?
The first derivative of \sqrt[6]{-x+1} is -1/(6(-x+1)^{5/6)}