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Popular >

y^'+y=1

Solution

y^{^{'}} + y = 1

Solution

y = - e^{- t - c_{1}} + 1

Solution steps

y^{'} (t) + y = 1

Solve separable ODE:

y = - e^{- t - c_{1}} + 1

y = - e^{- t - c_{1}} + 1

Popular Examples

y^{''}+4y^'+4y=4-t

y^{^{''}} + 4 y^{^{'}} + 4 y = 4 - t

integral of x/(x^3)

\int \frac{x}{x ^{3}} d x

integral of (x^3+e^x)

\int (x^{3} + e^{x}) d x

sum from n=1 to infinity of n^{0.5}

n = 1 \sum \infty n^{0.5}

tangent of (2x)/(x+1)tangent of

\frac{2 x}{x + 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=1 ?
The solution for y^'+y=1 is y=-e^{-t-c_{1}}+1