What is the derivative of sqrt(4-3x) ?

The derivative of sqrt(4-3x) is -3/(2sqrt(4-3x))

What is the first derivative of sqrt(4-3x) ?

The first derivative of sqrt(4-3x) is -3/(2sqrt(4-3x))

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\frac{d}{d x} (4 - 3 x)

- \frac{3}{2 4 - 3 x}

Solution steps

\frac{d}{d x} (4 - 3 x)

Apply the chain rule:

\frac{1}{2 4 - 3 x} \frac{d}{d x} (4 - 3 x)

= \frac{1}{2 4 - 3 x} \frac{d}{d x} (4 - 3 x)

\frac{d}{d x} (4 - 3 x) = - 3

= \frac{1}{2 4 - 3 x} (- 3)

Simplify

\frac{1}{2 4 - 3 x} (- 3) : - \frac{3}{2 4 - 3 x}

= - \frac{3}{2 4 - 3 x}

(19 x y^{2} + 11 y) + (19 x^{2} y + 11 x) (\frac{d y}{d x}) = 0

y^{^{''}} + 4 y = sec (2 x)

\frac{d}{d x} (- \frac{15}{16 x ^{\frac{7}{2}}})

x \to 0 lim (\frac{[ x ]}{x})

x \to 0 lim (\frac{sin ^{3} ( x )}{x})

What is the derivative of sqrt(4-3x) ?
The derivative of sqrt(4-3x) is -3/(2sqrt(4-3x))
What is the first derivative of sqrt(4-3x) ?
The first derivative of sqrt(4-3x) is -3/(2sqrt(4-3x))