What is the solution for ((9y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 ?

The solution for ((9y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 is

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((9y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0

(\frac{9 y ^{2} - t ^{2}}{y ^{5}}) \frac{d y}{d t} + \frac{t}{2 y ^{4}} = 0

y = \frac{- 9 + 2 c _{1} t ^{2} + 81}{2 c _{1}}, y = - \frac{- 9 + 2 c _{1} t ^{2} + 81}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 81 + 9}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 81 + 9}{2 c _{1}}

Solution steps

(\frac{9 y ^{2} - t ^{2}}{y ^{5}}) \frac{d y}{d t} + \frac{t}{2 y ^{4}} = 0

Solve exact ODE:

y = \frac{- 9 + 2 c _{1} t ^{2} + 81}{2 c _{1}}, y = - \frac{- 9 + 2 c _{1} t ^{2} + 81}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 81 + 9}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 81 + 9}{2 c _{1}}

y = \frac{- 9 + 2 c _{1} t ^{2} + 81}{2 c _{1}}, y = - \frac{- 9 + 2 c _{1} t ^{2} + 81}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 81 + 9}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 81 + 9}{2 c _{1}}

x^{2} - 2 x + 4, 2

\int_{0}^{1} \frac{1}{1 - x} d x

P (x) = x^{3} - 2 x^{2} + 2 x - 1

\int_{0}^{1} x x^{2} + 8 d x

y = 3 x + 1

What is the solution for ((9y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 ?
The solution for ((9y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 is