What is (\partial)/(\partial x)(5ycos(6x)) ?

The answer to (\partial)/(\partial x)(5ycos(6x)) is -30ysin(6x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(5ycos(6x))

\frac{\partial}{\partial x} (5 y cos (6 x))

- 30 y sin (6 x)

Solution steps

\frac{\partial}{\partial x} (5 y cos (6 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 y \frac{\partial}{\partial x} (cos (6 x))

Apply the chain rule:

- sin (6 x) \frac{\partial}{\partial x} (6 x)

= - sin (6 x) \frac{\partial}{\partial x} (6 x)

\frac{\partial}{\partial x} (6 x) = 6

= 5 y (- sin (6 x) \cdot 6)

Simplify

= - 30 y sin (6 x)

\int x^{2} ln (x^{2} + 1) d x

e^{- x} x^{2} + 3 e^{- x} - e^{- x}

x y^{^{'}} + y + x = 0, y (1) = 1

\frac{\partial}{\partial x} (ln (x^{5} - y^{4}))

\frac{d}{d x} (a cos (3 x))

What is (\partial)/(\partial x)(5ycos(6x)) ?
The answer to (\partial)/(\partial x)(5ycos(6x)) is -30ysin(6x)