What is the integral of 1/(cos(2*x)) ?

The integral of 1/(cos(2*x)) is 1/2 ln|tan(2x)+sec(2x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(cos(2*x))

\int \frac{1}{cos ( 2 \cdot x )} d x

\frac{1}{2} ln ∣ tan (2 x) + sec (2 x) ∣ + C

Solution steps

\int \frac{1}{cos ( 2 x )} d x

Rewrite using trig identities

= \int sec (2 x) d x

Apply u-substitution

: \int sec (u) \frac{1}{2} d u

= \int sec (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec (u) d u

Use the common integral:

\int sec (u) d u = ln ∣ tan (u) + sec (u) ∣

= \frac{1}{2} ln ∣ tan (u) + sec (u) ∣

Substitute back

u = 2 x

= \frac{1}{2} ln ∣ tan (2 x) + sec (2 x) ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ tan (2 x) + sec (2 x) ∣ + C

\frac{\partial}{\partial x} (3 x^{4} y^{2})

\int \frac{3 x}{4 - x} d x

\int x^{9} cos (x^{5}) d x

\int (4 csc (x) cot (x) + 2 sec^{2} (x)) d x

f (x) = \frac{1}{x ^{3}}

What is the integral of 1/(cos(2*x)) ?
The integral of 1/(cos(2*x)) is 1/2 ln|tan(2x)+sec(2x)|+C