What is the derivative of f(t)=106-80e^{-0.4t} ?

The derivative of f(t)=106-80e^{-0.4t} is 32e^{-0.4t}

What is the first derivative of f(t)=106-80e^{-0.4t} ?

The first derivative of f(t)=106-80e^{-0.4t} is 32e^{-0.4t}

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derivative of

f (t) = 106 - 80 e^{- 0.4 t}

32 e^{- 0.4 t}

Solution steps

\frac{d}{d t} (106 - 80 e^{- 0.4 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (106) - \frac{d}{d t} (80 e^{- 0.4 t})

\frac{d}{d t} (106) = 0

\frac{d}{d t} (80 e^{- 0.4 t}) = - 32 e^{- 0.4 t}

= 0 - (- 32 e^{- 0.4 t})

Simplify

= 32 e^{- 0.4 t}

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t e^{4 t}

What is the derivative of f(t)=106-80e^{-0.4t} ?
The derivative of f(t)=106-80e^{-0.4t} is 32e^{-0.4t}
What is the first derivative of f(t)=106-80e^{-0.4t} ?
The first derivative of f(t)=106-80e^{-0.4t} is 32e^{-0.4t}