What is the derivative of 7/(3x+4) ?

The derivative of 7/(3x+4) is -(21)/((3x+4)^2)

What is the first derivative of 7/(3x+4) ?

The first derivative of 7/(3x+4) is -(21)/((3x+4)^2)

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derivative of

\frac{7}{3 x + 4}

- \frac{21}{( 3 x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7}{3 x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{3 x + 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} ((3 x + 4)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 x + 4 ) ^{2}} \frac{d}{d x} (3 x + 4)

= - \frac{1}{( 3 x + 4 ) ^{2}} \frac{d}{d x} (3 x + 4)

\frac{d}{d x} (3 x + 4) = 3

= 7 (- \frac{1}{( 3 x + 4 ) ^{2}} \cdot 3)

Simplify

7 (- \frac{1}{( 3 x + 4 ) ^{2}} \cdot 3) : - \frac{21}{( 3 x + 4 ) ^{2}}

= - \frac{21}{( 3 x + 4 ) ^{2}}

t y^{^{'}} + 4 y = 0

\int \frac{1}{y ^{2} + 3} d y

\int_{- 1}^{1} \frac{6 x}{( x + 4 ) ^{2}} d x

n = 0 \sum \infty n (z - 1)^{n - 1}

\frac{\partial}{\partial x} (\frac{82}{5 + x ^{2} + y ^{2}})

What is the derivative of 7/(3x+4) ?
The derivative of 7/(3x+4) is -(21)/((3x+4)^2)
What is the first derivative of 7/(3x+4) ?
The first derivative of 7/(3x+4) is -(21)/((3x+4)^2)